Can I Get Some Help? :)
@phi
did u plug in the values and check?
first.. plug in the values of the first values in the table in the first choice..
I would use the idea that any number to the zero power is 1 in other words, \( 2^0=1\) and \( (\frac{1}{2})^0=1 \) and so on... I would replace x with 0 in each of the choices, and try to simplify can you do that ?
options a and b dont work. im trying c and d now
can you show what you did for the first choice?
the first choice is \[ 3(2)^x \] that means 3 times 2 to the x power. replace x with 0 so that it looks like this: \[ 3 \cdot 2^0\] what is 2^0 ?
ya..why won't a work @Axbeauty ?
remember order of operations: first do exponents (before multiplying)
oh.
would option A be my answer?
if we put in 0 for x, (and remember to do the exponent part first) the choices simplify to 3*1 2*1 3*1 2*1 or simply 3 2 3 2 the table shows for x=0 we want 3 so that means only choice a or c are possible
so you want to look at choice a and choice c try x=1 in choice a can you simplify \[ 3 (2)^1 \] ?
=6
yes, you get 3 * 2 which is 6 what does the table say we want for x=1 ?
3/2?
yes. and 6 is not 3/2 so that means choice a is not correct. by process of elimination , choice c is the answer. but we can double check.
choice c with x=1 is \[ 3 \left( \frac{1}{2}\right)^1 \]
first do the exponent part first: (½)^1 is just ½ so you have 3 * ½ if you multiply 3 *½ you get 3/2
Thank You :)
Join our real-time social learning platform and learn together with your friends!