Use inscribed rectangles to approximate the area under f(x) = –x2 + 7 for the –2 ≤ x ≤ 0 and rectangle width 0.5. 9.30 units2 9.75 units2 10.25 units2 10.75 units2
@phi
HI!!
Hey
this is going to take a lot of calculation
ok
first we need the endpoints of the intervals when we divide \([-2,0]\) in to pieces of length \(0.5\)
Ok would that be -2, -1.5, -0.5 and 0?
yes except you skipped one i think
-1
right
What do I do next?
ok next we see that it says "inscribed rectangles" it is clear that on the interval \([-2,0]\) your function \(-x^2+7\) is going up (increasing)?
Yes?
lol it is a parabola that opens down with vertex at \((0,7)\) so it should be clear |dw:1453211685987:dw|
ok
we need to know that so that we know the "inscribed rectangle" will use the left hand endpoints of your divided up intervals, not the right hand ones
So like on the negative side?
the interval you were given is \([-2,0]\) so yes, that is on the left of the graph, but that is not what i meant in the comment i just wrote let me try to draw a picture
|dw:1453211840476:dw|
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