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Mathematics 22 Online
OpenStudy (mathisfun13):

List the number of proper subsets of the set { 3,4,6,8}

OpenStudy (mathisfun13):

choices are 15 16 17 none of the above

zepdrix (zepdrix):

Let's ignore the word proper for a moment. Do you remember how to count the number of `subsets` of a set? :) It has something to do with powers of 2.

OpenStudy (mathisfun13):

I remember sort of

OpenStudy (mathisfun13):

16?

zepdrix (zepdrix):

So let's first figure out the number of `subsets` of our set. We'll go on to `proper subsets` after that. 2 raised to the power of the `cardinality of the set` gives us the number of subsets of the set. Cardinality is just the `number of elements` in the set. We have 4 elements. So 2^4 = 16. Good. But that's `subsets`, now for the restriction of `proper subsets`.

zepdrix (zepdrix):

The subset { 3, 4, 6, 8 } is NOT a proper subset. But every other subset is.

zepdrix (zepdrix):

The subset that is equal to itself, can't be proper.

OpenStudy (mathisfun13):

Okay

zepdrix (zepdrix):

So we need to subtract 1 from our total, simple as that! :)

OpenStudy (mathisfun13):

Thanks(:

zepdrix (zepdrix):

np

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