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Medal! Calculus! Question Below
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It gives you a hint to use \( \int \frac{1}{1+x^2} =\arctan(x) \). Then you can evaluate the result. \( \arctan(x) \bigg|_{-1}^{1} = \arctan(1) - \arctan(-1) \). Since \( \arctan(1)=\frac{\pi}{4}\), you get \( \frac{\pi}{4}\ - (-\frac{\pi}{4}\) \)
so the answer is pi/2? @DoughnutTable
well first we use the power of love the mathematically solve
and then you will find the answer deep within your heart
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