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Oxidation number of NaHSeO4? I think Na=1, H=-1, Se=8, O=-2. Am I right?
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Yes your answer appears to be correct.
Yep, unless there is a charge or ion, the sum of the oxidation states must be zero.
Thanks! But I think I noticed a mistake, shouldn't H be +1 making Se=+6?
Hmm yes Na and H would be +1 therefor Se would most likely be +6 sorry for the confusion
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