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CALC QUESTION: (Will medal) An object moves along the x-axis with velocity of v(t) = t(sqrt(2t+3)) -3t For which 't' is the object moving to the right?
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Will I have to integrate?
\[v(t) = t \sqrt{2t+3} - 3t\]
\[\int\limits_{?}^{?}t \sqrt{2t+3} - 3t?????\]
HI!!
Hi!
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no \(v\) is the velocity, same as speed except it can be positive or negative you are being asked where (for what value of \(t\) ) is it positive
Oh so I use the acceleration I found (second derivative)? Where would I go from there?
you are thinking too hard
if the velocity is positive, it is going to the right
Should I plug in 0 to the velocity function?
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\[t\sqrt{2t+3}-3t>0\] solve for \(t\)
Oh ok!
I got t > 3. Thank you! (Hope this is right) ((I need to be more confident).
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