Question

A quadratic equation is shown below:

3x2 − 16x + 2 = 0

Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (5 points)

Part B: Solve 9x2 + 3x − 2 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used. (5 points)

Answer 1

Part A)
The discriminant of 3x2 − 16x + 2 is 232. what does that tell us?

Answer 2

that its positive?

Answer 3

im very confused on how to do this

Answer 4

okay so the radicand tells us how many soulutions will have

Answer 5

we'll*

Answer 6

2

Answer 7

yes. That tells us there are 2 real solutions there is your answer to part a

Answer 8

Part B)
solve by factoring
9x2 + 3x − 2 = 0
(3x+2)(3x-1)=0
3x+2 = 0 or 3x-1 = 0

Answer 9

but for part a it says to show work i didnt really do any work

Answer 10

one second

Answer 11

???

Answer 12

okay back

Answer 13

\[ax^2+bx+c\]
\[3x^2-16x+2\]
what is a, b, and c

Answer 14

a= 3 b=-16 and c= 2

Answer 15

we will use discrimanant b^2-4ac which equals what?

Answer 16

plug in the letters for the numbers

Answer 17

would it be 256-24?

Answer 18

the value under the square root (b²-4ac) is called Discriminant (what i just gave you) and its value tells us about the nature of the roots of the equation.
If D = 0, the roots are real & equal
if D > 0, the roots are real & different
if D< 0, the roots are imaginary & different
(yes you are correct)

Answer 19

ok thats for part "b" right?

Answer 20

not really thajust for when you get your answers to part b

Answer 21

Part A)
The discriminant of 3x2 − 16x + 2 is 232. That tells us there are 2 real solutions

Part B)
solve by factoring
9x2 + 3x − 2 = 0
(3x+2)(3x-1)=0
equal each to 0
3x+2 = 0 or 3x-1 = 0
-2/3=x 1/3=x

Answer 22

hello?

Answer 23

hi sorry my computer died

Answer 24

@RhondaSommer

Answer 25

back

Answer 26

hi

Answer 27

back to the problem

Answer 28

@rhondasommer

Answer 29

yes sorry i was busy

Answer 30

well i did the question by myself i probably got it wrong but whatever thanks though.
@RhondaSommer

Answer 31

I legit gave you the answers \_(-.-)_/