I got D as my solution?!?

A easier one:
http://prntscr.com/9v8t09

Question

I got D as my solution?!?  


A easier one: 
http://prntscr.com/9v8t09

rishavraj · Answer

lol i suck at probbility and also i am not gonna count how many digits between then contains a 0 atleast ...lol and its kinda sure thing tht it would be 900 in denominator.....btw did u count the possibilities ??? @Agl202

phi · Answer

yes, that sounds good.

agl202 · Answer

K phi. Thx

rishavraj · Answer

yup thts correct

agl202 · Answer

@rishavraj I got 900 possibilities. :P

rishavraj · Answer

i meant about the 19*9 = 171 stuff

agl202 · Answer

Thx yall :)

phi · Answer

100 to 999 inclusive means you have 999 - 100 + 1 numbers
that equals 900

rishavraj · Answer

@Agl202  lol u welcome :P

agl202 · Answer

rishavraj · Answer

okkk

phi · Answer

if you count the number of ways to not get any 0's , it is
9*9*9
and 900-9^3  are the number of ways to have at least 1 zero
so  (900-729)/900 = 171/900

or you can just count the number that have at least 1 zero (not too hard)

agl202 · Answer

Yep that's how my work looked like :)

rishavraj · Answer

@phi nicce one....didn't think tht way :P