Question

Find the radius of a circle with the equation
x2 + y2 - 6x - 12y + 36 = 0

Answer 1

you can do this by completing the square and tracform the equation to
(x -a)^2 + (y - b)^2 = r^2

Answer 2

* transform

Answer 3

I'm not really sure how to do completing the square on this problem

Answer 4

complete the square on x^2 - 6x;-
Divide -6 by 2:-
= (x - 3)^2 - 9

Answer 5

and for y^2 - 12 y its
(y - 6)^2 - 36

Answer 6

x^2 + y^2 - 6x - 12y + 36 = 0
(x - 3^)2 + (y - 6( ^2 - 9 - 36 + 36 = 0
(x - 3)^2 + (y - 6)^2 = 9

compare this with the standard equation we have
r^2 = 9

so the radius r = 3