Question

x=6+y
x-3y=28

Answer 1

@welshfella could you help with this too?

Answer 2

you want to find the point where those two lines intersect?

Answer 3

it says find the system of the equations

Answer 4

Yeap, what method are you to use?

Answer 5

Usually the first you learn is substitution. But there is other methods aswell, and this can also easily be done by a CAS program.

Answer 6

im not entirely sure

Answer 7

@Tommynaiter I'm sure he just wants to know how to do it, not the method lol

Answer 8

Well, there is different ways to do it. And there is no point in learning him a method is isnt going to use in class.

Answer 9

Well I am making up this class. I just want to know how to do these. Im sure we will go back over them at a later date in my current class but I dont have time to wait till then. I just need to know how to do these.

Answer 10

But substitution would look like this: First isolate x or y in the first equation. Then insert the value in the 2nd equation. So you already have:
\[x=6+y\]Insert this value instead of x in the 2nd equation:\[x-3y=28<=>(6+y)-3y=28\]Now solve y, and insert the value to find x.

Answer 11

its easier to use elimination here
x = 6 + y
x = 28 + 3y

if we subtract these 2 equations x will be eliminated and we get
0 = 2y + 22

which we solve for y

Answer 12

the find x by substuting the y value we just found in x = 6 + y

Answer 13

so x=17?

Answer 14

both methods work well and give the answer
\[(-5, -11)\]

Answer 15

That was wrong...

Answer 16

nah cuz the first equation plug in -11 for y.

x = 6 + (-11)
x = -5

(-5, -11) is your answer

Answer 17

x = 6 + y = 6 - 11 = -5

so (-5,-11)

Answer 18

Still got it incorrect

Answer 19

The reason its says incorrect is because you make a mistake in transcribing the question
Correct is y = -6 + y

Answer 20

x = -6 + y
x = 28 + 3y
subtract 2nd - ist:-
0 = 34 + 2y
2y = -34
y = -17

and x = -6-17 = -23

solution is (-23, -17)