Question

Er... Someone please explain this?

Ine^1?

What is the In?

How do I solve an equation like this one?

Answer 1

\(\ln\) stands for \(natural\) \(logarithm\) or logarithm whose base is the irrational number \(e=2.718281828459045...\)
so, we can write:
\[\Large \ln {e^1} = k\]
where \(k\) is such that:

\[\Large {e^k} = {e^1}\]
what is \(k\)?

Answer 2

more precisely:
the subsequent formula:
\[\huge \ln {e^x} = y\]
where \(x,y\) are two appropriate real numbers, is, according to the definition of logarithm, equivalent to this one:
\[\huge {e^y} = {e^x}\]

Answer 3

the last equation, holds, if and only if:
\[\huge y = x\]

Answer 4

OH I feel so dumb... I get it, sorry. :D That was actually really simple.