Question

HELP PLEAASEEE !!!!!!!!!!! Probability theory predicts that there is a 22.4% chance of a particular soccer player making four penalty shots in a row. If the soccer player taking four penalty shots is simulated 2500 times, in about how many of the simulations would you expect at least one missed shot? A.194 B.560 C.56 D.1940

Answer 1

please help @kropot72

Answer 2

@JessicaH123

Answer 3

What is the probability of missing one or more of the 4 shots in a row, given that the probability of getting 4 shots in a row is 0.224?

Answer 4

DO I MULTIPLY?

Answer 5

help please @owen3

Answer 6

Let the event 'make four shots in a row' be A, and the the event 'miss one or more of the 4 shots in a row' be B.
Now we can write:
P(A) + P(B) = 1
Given that P(A) = 0.224, what is the value of P(B)?

Answer 7

1?

Answer 8

Not really. You need to substitute the given value of P(A) into the equation. Then solve it to find the value of P(B).

Answer 9

Then, the solution is found by multiplying P(B) by 2500.