Will give medal for help let isosceles ∆ABC have congruent sides AB and BC. Let M be the midpoint of AC. Prove that ∆ABM and ∆CBM are congruent by showing that all corresponding sides are congruent. You will need to justify these three statements: AB = CB BM = BM MA = MC
@Brill
Alright well it's been awhile since I've taken Geometry but I'll try to piece this together. We absolutely know that two legs are congruent in an isosceles triangle AB and BC. We also know that the midpoint of AC means that it splits leg AC perfectly in the middle so both sides are also equal to each other. What can we conclude from this info?
I already have the answer but thank you
Just out of curiosity was my approach correct then? In terms of justifying, the top and third are correct and the middle one shouldn't be I believe.
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