Solve the quadratic equation using the quadratic formula.
6x²- 9x + 2 = 0
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RhondaSommer (rhondasommer):
I can help
OpenStudy (youngjuvie):
\[x=\frac{ 9\pm \sqrt{33} }{ 12 }\]
RhondaSommer (rhondasommer):
\[(-b +/- √b^2-4ac)/2a\]
OpenStudy (youngjuvie):
by Solve the equation for x by finding a,b, and c of the quadratic then applying the quadratic formula
OpenStudy (neverendingcycle):
is this a middle school question?
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OpenStudy (youngjuvie):
decimal form x≈1.22871355,0.27128645
RhondaSommer (rhondasommer):
6x²- 9x + 2 = 0
a b c
RhondaSommer (rhondasommer):
not realy more like 8th and 9th grade depending how advanced you are
OpenStudy (neverendingcycle):
im in 8th grade and i have this question on a test but I never read about this in my studies.
RhondaSommer (rhondasommer):
@youngjuvie you are not explaing your answer. also; you answer isnt entirely correct. please stop or i will report you
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OpenStudy (youngjuvie):
what grade ae u in
OpenStudy (neverendingcycle):
8th
RhondaSommer (rhondasommer):
oh cool yeah I can help you with this
RhondaSommer (rhondasommer):
so you know how a quadratic equation is written as this right? \[ax^2+bx+c\]
OpenStudy (neverendingcycle):
no i don't even know what quadratic means
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RhondaSommer (rhondasommer):
involving the second and no higher power of an unknown quantity or variable
RhondaSommer (rhondasommer):
its a graph basically
OpenStudy (neverendingcycle):
i haven't learned this yet, but it is on a test
RhondaSommer (rhondasommer):
idk your teacher is wierd
OpenStudy (neverendingcycle):
okay
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OpenStudy (neverendingcycle):
home schooled
OpenStudy (neverendingcycle):
my computer is my teacher
RhondaSommer (rhondasommer):
so the equations are this \[ax^2+bx+c\] with \[a,b,c\] as your co-efficients(numbers)
OpenStudy (neverendingcycle):
okay
RhondaSommer (rhondasommer):
lol me; but i started just this year
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OpenStudy (neverendingcycle):
i started last year
RhondaSommer (rhondasommer):
\[6x²- 9x + 2 = 0\] is your equation with a=6 b=-9 and c=2
RhondaSommer (rhondasommer):
nice; lmk if you need help with anything ever ^_^ 8th was my best year with grades
OpenStudy (neverendingcycle):
okay i will fan you so i can remember your name
OpenStudy (neverendingcycle):
thanks for your help!
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RhondaSommer (rhondasommer):
so you have this as your quadratic "equations"
\[-b+√(b^2-4ac)/2a\]\[-b-√(b^2-4ac)/2a\]
OpenStudy (neverendingcycle):
okay
RhondaSommer (rhondasommer):
im helping you get the answer to this...did you not want that?
OpenStudy (neverendingcycle):
no i do
RhondaSommer (rhondasommer):
oh okay :)
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OpenStudy (neverendingcycle):
:)
RhondaSommer (rhondasommer):
a=6 b=-9 and c=2 so plug those numbers into the first equation
OpenStudy (neverendingcycle):
okay
RhondaSommer (rhondasommer):
\[−b+√(b^2−4ac)/2a\]
\[(9+√(-9)^2-4(6)(2))/2(6)\]
OpenStudy (neverendingcycle):
ohh okay that makes more since
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RhondaSommer (rhondasommer):
so solve that while i solve the second equation :)
OpenStudy (neverendingcycle):
okay
RhondaSommer (rhondasommer):
OpenStudy (neverendingcycle):
i got 14 for my equation
RhondaSommer (rhondasommer):
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RhondaSommer (rhondasommer):
you shouldnt have gotten 14 :/
OpenStudy (neverendingcycle):
well i stink at equations then :/
RhondaSommer (rhondasommer):
thats what you should have gotten... :/ i dont think you stink I think you needed an easier problem XD
OpenStudy (neverendingcycle):
yes i think that to
RhondaSommer (rhondasommer):
would you be wiling to do an easier problem that has a whole number as an equation?
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RhondaSommer (rhondasommer):
not equation
answer*
OpenStudy (neverendingcycle):
um, i think I will have to say not to that. Not because I don't like you, but because this is like a "what grade level is your math at" type of test so I don't think I will have to deal with that type of problem for a while. Thanks for all of your help though!