Find the minimum value of the function f(x) = x^2 + 5x - 6.
I keep getting -2.500 but apparently thats wrong
it's the vertex
can u put it in vertex form?
LOL ur close with 2.5.
Do you know differe,tiation
Do you know differe,tiation
u solved for the X instead of the y
waaiiittttt......
I think ur right.
First, please recognize that f(x) = x^2 + 5x - 6 has a graph which is a parabola. Does the parabola open up or down? If you're still in algebra, use the formula x=-b/a to calculate the x-coordinate of the vertex of the parabola. Then find the value of f(x) there. Then you'll have your coordinates of the minimum.
if u derive the equation u get 0=2x+5
in which case x=-2.5
Then plug that into the equation and see what u get for y!
that is to say, if you find the derivative of f(x) and set the derivative = to zero and solve for x, you'll get that x=-2.5. Find the associated y value. Write the two coordinates in the form (x,y). That's the minimum of this function.
yeah, what @mathmale said
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