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Find dy/dx if f(x) = (x + 1)^(2x)
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method one take the log take the derivative of the log after "simplifying using property of the log then multiply your result by the original function
method two rewrite \[f(x)=(x+1)^{2x}\] as, by definition \[\large e^{2x\ln(x+1)}\] then take the derivative of that using the chain rule all the actual work will be the same
if you do it both ways you see that the real work is finding the derivative of \[2x\ln(x+1)\] using the product rule
you good from there?
I got (2ln(x+1)+2x/x+1)(x-1)^(2x)
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me too
thank you so much!
yw
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