Question

help will fan and medal

Answer 1

Given it is a parallelogram, then DH = HF and GH = HE
DH = HF
x+1 = 3y (eq1)
GH = HE
3x-4 = 5y+1 (eq2)
Two equations, two unknowns, solve.
it is easiest to probably rearrange eq1 so it says x= _______ by subtracting 1 from both sides
x+1=3y (eq1)
x = 3y - 1 (eq3)
then you can substitute the x of eq3 into eq2.
3x-4 = 5y+1 (eq2)
3(3y - 1)-4 = 5y+1
and solve for y
9y - 3 - 4 = 5y+1
9y-7=5y+1
4y=8
y=2
then substitute y=2 into the original eq1 or eq2, whichever is easier to solve. (where there is a y, put a 2 instead.)
x+1 = 3y (eq1)
x+1 = 3(2)
x+1 = 6
x=5