Simplify √72/54?? PLEASE HELP I'LL AWARD AND FAN!!!
Is it like this?\(\Large\sqrt{\frac{72}{54}}\)
Or like this? \(\Large\frac{\sqrt{72}}{54}\)
It's the 1st one :)
Okay, so that simplifies to \(\Large\frac{\sqrt{72}}{\sqrt{54}}\) To simplify the radicals, you need to factor the numbers underneath.
okay
so divide by 2?
Yes.
What is 72 divided by 2?
23
no.
i meant 36 oops sorry
and 54 divided by 2 is 27
yes, Okay, so you get \(\Large\frac{\sqrt{36\times2}}{\sqrt{27\times2}}\rightarrow\frac{\sqrt{36}\sqrt{2}}{\sqrt{27}\sqrt{2}}\rightarrow?\) What does \(\sqrt{36}\) equal? And you need to factor the 27 now
27 is factored to 9, which can be factored to 3
is that it?
Sort of. You get \(\Large \frac{\sqrt{36}\sqrt{2}}{\sqrt{9}\sqrt{3}\sqrt{2}}\) You need to simplify it now.
square root 8 over 7??
sorry this is all very confusing for me
Okay, let's take it one step at a time. What is \(\Large \sqrt{36}\) equal to?
square root 3?
No. The square root of 36 is 6, remember? What is the square root of 9?
ooh, the square root of 9 is 3
so whats the next step?
right. So that simplifies to \(\Large\frac{6\sqrt{2}}{3\sqrt{3}\sqrt{2}}\) Now, you need to combine the \(\large\sqrt{3}\) and \(\large\sqrt{2}\), and simplify the 6/3
would that be radical 5 and then 2/3
is that okay??
Uh, no. It would be \(\Large \sqrt{3}\sqrt{2}=\sqrt{3\times 2}=\sqrt{6}\) And 6 divided by 3 is not 2/3
oh, 2 then
so what would the answer be?
are you still there?
Yes, so the final answer is \(\Large\frac{2\sqrt{2}}{\sqrt{6}}\) Unless your teacher doesn't want a radical in the denominator, in which case, we have more work to do
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