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Mathematics 19 Online
OpenStudy (anonymous):

Find the integral

OpenStudy (anonymous):

myininaya (myininaya):

have you tried integration by parts?

myininaya (myininaya):

make x^(1/2) your integrating term make ln(x) your differentiating term

OpenStudy (solomonzelman):

\(\color{#000000 }{ \displaystyle \int \sqrt{x}\ln(x)~dx }\) \(\color{#000000 }{ \displaystyle \frac{2}{3}\int \sqrt{x}\ln(x^{3/2})~dx }\) \(\color{#000000 }{ \displaystyle u=x^{3/2} }\) \(\color{#000000 }{ \displaystyle du= \frac{3}{2}x^{1/2}~dx\quad \Longrightarrow \quad \frac{2}{3}du= x^{1/2}~dx }\) \(\color{#000000 }{ \displaystyle \frac{4}{9}\int \ln(u)~du }\) That would be, if ln(u) is an automatic integral for you... In general, myininaya's approach is better...

OpenStudy (solomonzelman):

Just looking at a different angle.

myininaya (myininaya):

that is really good looking @SolomonZelman one can skip the integration by parts if they are allowed to remember the integral of ln(u) w.r.t. u

OpenStudy (solomonzelman):

Yes, that would be a nice approach\(: ) \) Of course one can derive the general antiderivative of \(x^n\ln(x)\), using this trick.

OpenStudy (anonymous):

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