Mathematics
23 Online
OpenStudy (studygurl14):
calculus @solomonzelman
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (studygurl14):
derivative of...
OpenStudy (studygurl14):
Should I pull out the exponent 2 first?
OpenStudy (xapproachesinfinity):
product and chain rule
OpenStudy (xapproachesinfinity):
you can if you did (sqrt6 x)^2
OpenStudy (solomonzelman):
\(\color{#000000 }{ \displaystyle 4x^5\ln(6x^2) }\)
\(\color{#000000 }{ \displaystyle 8x^5\ln(6x) }\)
\(\color{#000000 }{ \displaystyle 8x^5\ln(x)+8\ln(6)x^5 }\)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (xapproachesinfinity):
i would just use chain rule directly if it was me
OpenStudy (solomonzelman):
So, the second part is just power-rule, and first is just product...
There are several ways to do the problem, tho'.
OpenStudy (xapproachesinfinity):
or like solo just did use log property of product
OpenStudy (studygurl14):
Oh, right...anyway, would the derivative of \(\large \ln(6x^2) = 2\Large \frac{1}{x^2}\)
OpenStudy (studygurl14):
sorry, ignore the set up there, I was solving in my head as I was typing the LaTeX
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (xapproachesinfinity):
no x^2 at bottom is not good
OpenStudy (solomonzelman):
\(\color{#000000 }{ \displaystyle \ln(6x^2)=\frac{1}{6x^2}\times \left[\frac{d}{dx}~6x^2\right] }\)
OpenStudy (solomonzelman):
using the chain rule.
OpenStudy (studygurl14):
Ah, so 2/x?
OpenStudy (solomonzelman):
precisely;)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (xapproachesinfinity):
yes
OpenStudy (studygurl14):
Thank you both!
OpenStudy (xapproachesinfinity):
welcome
OpenStudy (solomonzelman):
Just to verify, if you want, you can post the final answer for check.
OpenStudy (solomonzelman):
or, you can check it through wolf..