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How to simplify this?
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\[[(t+1)^{2/3}\times3(2t^2-1)^2\times4t] + [ \frac{ 2 }{ 3 }(t+1)^{-1/3}\times (1) \times (2t^2-1)^3]\]
uhg thats ugly
my skills lack in this area :(
wolframalpha yeah
the finished product would look \[\frac{ 2 }{ 3 }(t+1)^{-1/3}(2t^2-1)^2[18t(t+1)+(2t^2-1)]\]
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But, I need to know how to do it algebraically in-case I have to do this on exams lol
Haha I gotcha ok lets see
No calculators allowed too
I thought you were just simplifying a derivative :P
as a final answer
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I already did the derivative part, I just need to clean up the ugly part and simplify it
|dw:1454844961193:dw|
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