Question

Solve for x.

Answer 1

\(\large \frac{2x-2}{5} + 10 = \frac{9x}{30}\)

Answer 2

I thought of bringing \(\frac{9x}{30}\) to the other side by combining it with \(\frac{2x-2}{5}\). Will that still work?

Answer 3

Before doing anything else, identify your LCD. Then, eliminate the fractions in your given expression. Only then should you try to solve the equation.

Answer 4

OK. So would the LCD be 30?

Answer 5

Yes. Now clear your equation of fractions.

Answer 6

go to math papa and type your question it will show work and give u answer

Answer 7

Does that mean that I should have, let's say, \(\frac{2x-2}{5}\) mutliplied by \(\frac{6}{6}\) to get the denominator of 30?

Answer 8

I think that that won't cancel out the fraction.

Answer 9

That's one approach. It will "work."
You could also try multiplying each of your 3 terms by 30 and cancelling wherever possible. Please show your work.

Answer 10

Oh I get the second approach now.

Answer 11

30 times (2x-2)/5 is 6(2x-2), which can be simplified further.

Answer 12

After I multiplied each of the terms by 30, I got \(12x - 12 + 30 = 9x\).

Answer 13

Is 30*10=30?

Answer 14

Oh sorry. It's 300.

Answer 15

Right. Finish your solution, and then by all means check your solution back into the original equation.

Answer 16

I got x = -76

Answer 17

Hey can i ask you a question