Question

Giving Lessons: Translating Phrases into Algebraic Expressions

Answer 1

If you don’t already know… for the past few days I have decided to start Giving Lessons. If you want to see the rest of them just go on my profile, click on my questions, and click on the ones that start with: “Giving Lessons”. I feel that this is definitely helping some of you, so I decided that this is a great way to help you guys out! If you already know this, then tag someone who doesn’t, but if you don’t already know this, then hopefully this will help you out!

Let’s get started! :)

The first sample problem is:

\(\color{green}{\text{The quotient of e plus 2 and 5 result in 4}}\)

Alright, this may sound a bit complicated but you have to read it part by part slowly and then you will be able to comprehend it perfectly.

So, we know that \(\color{purple}{\text{quotient}}\) is the answer to a division problem, so there has to be some division involved here.

Now the first part of the problem is \(\color{purple}{\text{"The quotient of e plus 2 AND 5”}}\). The and clearly separates the 2 phrases meaning that \(\color{purple}{\text{e plus 2}}\) probably goes together and \(\color{purple}{\text{5}}\) is separated from those two. So, the first step is to write \(\color{purple}{\text{e plus 2}}\). We would write that as \(\color{purple}{\text{e + 2}}\).

Now the AND 5 shows that it is e plus 2 OVER 5, because we have to divide since we need the quotient of e plus 2 and 5. So we would write that as \(\color{purple}{\frac{ e + 2 }{ 5 }}\). We have now completed the first part of this and the last part is simply \(\color{purple}{\text{“results in 4”}}\). This means that the whole problem equals 4. So we would write that as \(\color{purple}{\frac{ e + 2 }{ 5 } = 4}\).

DONE! GREAT JOB! :)

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Still Confused? Don’t worry! We will be doing another sample problem!

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Okay, our next sample problem is:

\(\color{green}{\text{4 multiplied by the sum of y and 7 is equal to 16}}\)

Now first we need to separate the “parts” of the problem. Now "4 multiplied by" is one part, "the sum of y and 7" is the second part, and "is equal to 16" is the last part.

We simply need to take that information and put that together. So “4 multiplied by” is \(\color{purple}{\text{4 * ?}}\). The question mark is whatever it is going to be multiplied by, which is the sum of y and 7. We would write “the sum of y and 7” like \(\color{purple}{\text{y + 7}}\). Now when we put it together we should get \(\color{purple}{\text{4(y + 7)}}\).

However, that is not all. We still have the last part which is \(\color{purple}{\text{“is equal to 16”}}\). Now that simply means that we have to add \(\color{purple}{\text{ = 16}}\) at the end of it.

Finally, our answer should be \(\color{purple}{\text{4(y + 7) = 16}}\).

DONE! GREAT JOB! :)

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Still Confused? Don’t worry! We will be doing another sample problem!

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Okay, our next sample problem is:

\(\color{green}{\text{The square root of the sum of c and 1 equals 9}}\)

This one is a bit more complex, but it is not at all harder.

Now once again we need to take out the “parts”. Our first part is \(\color{purple}{\text{the square root of the sum of c and 1}}\) and our second part is \(\color{purple}{\text{equals 9}}\). That is all!

To write the square root of the sum of c and 1, it is simply \(\color{purple}{\text{c + 1}}\) in a square root. So, we would write that as \(\color{purple}{\sqrt{c + 1}}\). Now we just need to add \(\color{purple}{\text{ = 9}}\) to the end of it.

So, our final answer is \(\color{purple}{\sqrt{c + 1} = 9}\).

DONE! GREAT JOB! :)

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Still Confused? Don’t worry! We will be doing one LAST sample problem!

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Okay, our LAST sample problem is:

\(\color{green}{\text{Subtracting three-fourths of y from 7 results in 19}}\).

This one is also a lot more complex, but not in the difficulty, simply in the amount of steps.

First, as always, we get the parts. The first part is \(\color{purple}{\text{subtracting three-fourths of y}}\), the second part is \(\color{purple}{\text{from 7}}\), and the last part is \(\color{purple}{\text{results in 19}}\).

Now to write the first part it is simply a fraction of y. So we would write that as \(\color{purple}{\frac{ 3 }{ 4 }y}\).

For the second part, since the fraction is being subtracted FROM 7, we would simply place 7 in front of the fraction, followed by a minus sign. Now when we do this, we should have \(\color{purple}{{7 -}\frac{ 3 }{ 4 }y}\)

Now just add \(\color{purple}{\text{=9}}\) to it and we are done! So the answer is \(\color{purple}{{7 -}\frac{ 3 }{ 4 }y = 9}\)

That’s It! :)

DONE! GREAT JOB! :)

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Still Confused? Don’t Worry! If you have any questions just comment them down below! I will try my best to answer them as soon as possible!

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I hope this helped you in some way! Once again, If you already knew this, then tag someone who doesn’t. But if you didn’t and this helped you… then I am very glad that I helped you out!

Alright, bye now! :)

Answer 2

Thank you @DanJS for the idea :)

Answer 3

Can you tell me what you think? :) @Conqueror @freckles @imqwerty

Answer 4

I just tagged you guys because you are pretty much the experts so I was wondering if you could give some feedback? :)

Answer 5

everything looks great
though 19 changed to 9 in the last example :p

Answer 6

lol expert . yeah right,

just remember enough of the landscape to still be able to move around diff areas

Answer 7

Haha okay thanks guys! :)

@freckles @DanJS

Answer 8

can you help me with a question?

Answer 9

@mathmath333 @mathstudent55 @pooja195

What do you guys think? Can you give me some feedback? :)

Answer 10

@AihberKhan Give a lessons on multidimensional vectors.

Answer 11

I will definitely try when I have time! :)

@Comrad

Answer 12

@AihberKhan Very nice job!

Answer 13

Thank you! I appreciate it! :)

@mathstudent55

Answer 14

Very nice explanation :) awesome tutorial! :D @AihberKhan

Answer 15

Thank you so much! I appreciate your feedback! :)

@imqwerty

Answer 16

Great Explanation ^^ Like @freckles said 19 got changed to 9 but we all sometimes write one thing while we mean another xD

\(\LARGE\color{#800000}{Overall...Great~Job!:)}\)

Answer 17

Haha yeah I saw that :P

Silly mistake xD

Thank you so much for the great feedback! :)

@563blackghost