Please help Solve 3(tan^4(x))+4(tan^2(x))-1=0 I know there are multiple situations but I was wondering how to solve this algebraically like a polynomial without graphing
Not situations, solutions
plug it in here for great explanation be sure to plug in
Umm actually that doesn't work because it asks for an upgrade for step by step solutions
There should be no plugging in. Solve this: \(3x^{2}+4x-1 = 0\)
\[x=\frac{ -2\pm \sqrt{7} }{ 3 }\]
That's what I got Would that squared be equivalent to using the 4th power instead of the second like we did?
Okay, now write \(\tan^{2}(x) = \dfrac{-2\pm\sqrt{7}}{3}\), think about why I did that, and you're almost done.
Ohhhhh Wow that makes sense, thanks a lot!
You would take the square root of that expression and get \[\tan x=\sqrt{\frac{ -2\pm \sqrt{7} }{ 3 }}\] right?
No quite. Add another \(\pm\)
Oh right in front of the square root Thank you!
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