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Let f(x) = 2x + 2. Solve f^−1(x) when x = 4. 1 3 4 10
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i need an explanation, i'm really bad at this lol
this is exactly the same as being asked: "solve for \(x\) if \(2x+2=4\)"
it is just worded funny is all
thats the inverse?
so x=1?
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no one but a math teacher writes "solve for \(f^{-1}(x)\) if \(x=4\) must more natural to say "find \(f^{-1}(4)\)
yes
oo ok, can you help me with another to make sure i get it?
if \[f(x)=2x+2\] then \[f(1)=4\] so \[f^{-1}(4)=1\]
sure
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Let f(x) = 2x − 6. Solve f−1(x) when x = 2. −5 4 −2 7
ok so, it would be 2x-6=2
yes
and x=4
yes
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thank you soooo much!
yw, you did almost all the work!
i have a couple more but ill post in another question
k
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