Which equation describes a parabola that opens left or right and whose vertex is at the point (h,v)?
a. y=a(x-v)^2+h
b. x=a(y-v)^2+h
c. x=a(y-h)^2+v
d. y=a(x-h)^2+v

Question

Which equation describes a parabola that opens left or right and whose vertex is at the point (h,v)?
a. y=a(x-v)^2+h
b. x=a(y-v)^2+h
c. x=a(y-h)^2+v
d. y=a(x-h)^2+v

anonymous · Answer

are you still there @clamin

shouborno · Answer

|dw:1455004359526:dw|

Since the vertex is $ (h,v) $ , the equation is, $ x-h = a(y-v)^2\;, \;\;\;or,\;\;\;y-v=a(x-h)^2$ 

Now, if we put $y=v+1,v-1$  in the equation $(b)$, we get the same value of $x$, that is, $x=a+h$.
On the other hand, let's put $x=h+1,h-1$ in the latter equation. Similar to the first equation, we get $y=a+v $.

$\therefore $ We deduce, $(b)$ opens either right or left, according to the graph plotted above.  $QED$