Question

what is the vaule of f^1 (f(x))

Answer 1

????????

Answer 2

that's what the question was

Answer 3

does it say what x is

Answer 4

no it wants the vaule of what i put in its 0,1 ,x,x^-1

Answer 5

oh dang man i dont know what to say about that im sorry
what about you @phi

Answer 6

man i need help

Answer 7

@welshfella can you help out on this one

Answer 8

nvm it was x i guessed and failed the test

Answer 9

i can give you a direct answer but that s not allowed

basiccally what we have here is the x of a function being replaced by the inverse of the function.

Answer 10

yes it is x

Answer 11

thanx @welshfella

Answer 12

lets try a simple one to illustrate

f(x) = 2x
]
y = 2x
x = y / 2
so f-1(x) = x/2

f-1(fx) = 2 * x/2 = x

Answer 13

you lost me i am good at math but that is confusing

Answer 14

inverse functions can be confusing.
but if you have a pair (x,y)
we say we "put x into" some function, and it "returns" y
(maybe like a vending machine: money in, candy out"
the "inverse function" does it the other way round: you put in y and get out x

so if you do \[ f^{-1}(f(x)) \]
the f(x) "returns" y
\[ f^{-1}(y) \]
and if you put y into the inverse function, you get back x
\[ x= f^{-1}(y) \]
in other words
\[ x= f^{-1}(f(x)) \]

It gets confusing, because people always use "x" as the input variable
even when writing down the inverse function: \( f^{-1}(x) \)
so you have to remember that "x" is the "y" of the f(x) function. *very confusing*