Question

9 + 10

Answer 1

huh?

Answer 2

What is it

Answer 3

Cmon man

Answer 4

Count? use your fingers or something to count

Answer 5

I dont have any

Answer 6

TELL ME

Answer 7

Count? use your fingers or something to count

Answer 8

);

Answer 9

Does anyone know

Answer 10

21 xD

Answer 11

Oh ok thx

Answer 12

just kidding

Answer 13

U LIAR

Answer 14

I almost got it wrong

Answer 15

lol use a calculator

Answer 16

WHT IS IT

Answer 17

How do u type.

Answer 18

We are all dome

Answer 19

Plz owl

Answer 20

@Owlcoffee will do the magic <3

Answer 21

I hope

Answer 22

Wait let me ask me freind hopefully the teach wont see

Answer 23

ok I got it he got 109

Answer 24

That wasnt hard

Answer 25

ok by

Answer 26

Let us consider the following body of numbers which we will only consider 9 of, thereby, we'll name the variable "beta" as one varying inside the set from 1-9:
\[\beta : \prod_{\beta \in \mathbb{N} }^{9} \iff \beta \in (1,9)\]
And the same for an alpha that goes from 1 to 10:
\[\alpha: \prod_{\alpha \in \mathbb{N}}^{10} \iff \alpha \in (1,10)\]
Now, we will consider the operation of alpha and beta:
\[\alpha \times \beta \rightarrow \mathbb{N} \iff \prod_{\alpha \in \mathbb{N}}^{10} \times \prod_{\beta \in \mathbb{N}}^{9} \rightarrow \mathbb{N}\]
Therefore, we will consider the natural as the sum operative of the following:
\[+ : \prod_{\alpha \in \mathbb{N}}^{10} \times \prod_{\beta \in \mathbb{N}}^{9} \rightarrow \mathbb{N} : \alpha \times \beta \]
And there, we will say:
\[+: \prod_{\alpha \in \mathbb{N}}^{10} \times \prod_{\beta \in \mathbb{N}}^{9} \rightarrow \alpha \times \beta = 10+9=19\]

Answer 27

OH

Answer 28

@Owlcoffee Brilliant :*

Answer 29

WOW

Answer 30

@Somy <3

Answer 31

lol what does that mean

Answer 32

Dont take 20mins

Answer 33

Do you have the key to enginuty?

Answer 34

19 !!!!!!!!!!!!!!!!!!!