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Mathematics 23 Online
OpenStudy (ohmath123):

How do i find the range for x+4/x+2. I know to find range i need to solve the equation. But how do i do that?

OpenStudy (anonymous):

oh range, not domain, sorry

OpenStudy (anonymous):

you have a couple choices for finding the range. the easiest is to think a number is only one if the numerator and denominator are equal in this case you have \(x+4\) in the numerator and \(x+2\) in the denominator and since it is not possible for \(x+4\) to be equal to \(x+2\) this sucker is never equal 1

OpenStudy (ohmath123):

I know the domain is all real numbers except -2 right? @satellite73

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

your other choice, much less fun than thinking, is to try to solve \[y=\frac{x+4}{x+2}\] for \(x\)

OpenStudy (anonymous):

that will give you the inverse function find the domain of the inverse function, that will be the range of this one

ganeshie8 (ganeshie8):

You may use componendo and dividendo to solve \(x\) here

OpenStudy (anonymous):

@ganeshie8 lets keep it clean please

OpenStudy (anonymous):

actually i had to look that up to see what it meant !

ganeshie8 (ganeshie8):

it is actually more cleaner than the mess that we get by doing cross multiplication, grouping, and isolating

OpenStudy (anonymous):

expand!

ganeshie8 (ganeshie8):

just want to let the op know that there is something called "componendo and dividendo" i don't want him to master this method in this thread haha

OpenStudy (anonymous):

dang i have to look it up again and try it myself then!

ganeshie8 (ganeshie8):

https://brilliant.org/wiki/componendo-and-dividendo/

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