Identify the initial amount a and the growth factor b in the exponential function. g(x)=14*2^x Medal, fan, and testimonial for quick accurate responses!!!
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can anyone help? I don't understand how to do it
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Initial Amount is x = 0
\[y = a b^{x}\] Take this general equation. You can see that as \[x \ increases\ b^x \ increases \] similarly \[x \ decreases\ b^x \ decreases \] and value of a will not change because there is no variable factor like x with it.
I can try. But not right now.
can you walk be through it step by step with my problem?
Did you understand it for general equation? Where you have doubt?
I don't understand it. I have no clue what to do.
ok be relax.
g(x)=14*2^x
you know that \[2^2, 2^3, 2^ 4....\] Here you can see that as the power of 2 increases its value increases. Now \[2^2, 3^2, 4^2, 5^2...\] Here its exponent is constant but base value is changing which affecting the overall value.
ok
So you know that value in this sequence \[2,2^2,2^3,2^4,....\], in this continuous sequence you can see 2 is changing the previous value \[2^2 = 2.2 \\ 2^3 = 2^2.2 \\2^4 = 2^3.2\] So everytime 2 has effect on the growth of the sequence
ok.....
so in your equation which value/term you think is growth factor?
i have no clue. Can you explain it differently? Or someone else explain it?
14, 2, x which you think is initial amount which is not changing relate it to this \[g(x) = ab^x\]
I'm sorry. I get that you are trying to explain this, but i have no clue what you mean
growth factor is a value which multiplies itself over time. Suppose our hair, in our initial days our hair was small but with years they are getting longer so each day/months/year its getting long even by 1cm per month. So here growth factor is 1. Similarly for \[g(x) = 14.2^x\] here 2 is getting multiple by itself x number of times. You can take 2 as hair growing per year and x as your age or any age.
ok....
nevermind. this isn't helping. It's been an hour and i have learned nothing. i am going to email my teacher and hope she responds.
Really sorry for that. Hope I will improve in the teaching aspects.
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