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Algebra 19 Online
OpenStudy (anonymous):

please check my answer in algebra II!!! will fan and medal

OpenStudy (anonymous):

OpenStudy (anonymous):

is it (1,3)??

OpenStudy (anonymous):

@isaidavila could you help me on this one too?

OpenStudy (anonymous):

@stylesprettygirl do u know?:(

jimthompson5910 (jim_thompson5910):

each row of this table represents the bottom row like it is shown in this example here http://www.purplemath.com/modules/synthdiv.htm

jimthompson5910 (jim_thompson5910):

they are compacting things so in a sense, there are 4 different tables combined to form 1 big table

OpenStudy (isaidavila):

Sorry don't know

jimthompson5910 (jim_thompson5910):

The first value in each row is known as the test root IF the last value in that same row is 0, then the remainder is 0 and that corresponding test root is an actual root. Otherwise, it is not For instance, 3 is a test root in the bottom row. Since 17 is the remainder, we conclude that x = 3 is NOT a root of f(x). We can say f(3) = 17

jimthompson5910 (jim_thompson5910):

hopefully this is making sense @elizabethroland53 ?

OpenStudy (anonymous):

ohhh so its (3,17)?

jimthompson5910 (jim_thompson5910):

(3,17) is a point on f(x) they're asking for points that are not on f(x)

jimthompson5910 (jim_thompson5910):

why is (3,17) a point on f(x)? because using 3 as a test root yields a remainder of 17 (bottom row) This is based on the remainder theorem http://www.purplemath.com/modules/remaindr.htm

OpenStudy (anonymous):

ohoh wait so that would mean its (-1,-1) right???

jimthompson5910 (jim_thompson5910):

yep, since it should be (-1,-11)

OpenStudy (anonymous):

that does make total sense thank u!

jimthompson5910 (jim_thompson5910):

you're welcome

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