Question

First person to solve gets medal, fan, and help in another subject.

Answer 1

\[a^2+b^2 = c^2\] this is pythagorean theorem

Answer 2

Like it says, use the Pythagorean theorem.

\(\sf a^2 + b^2 = c^2\)

Where 'a' and 'b' are the two legs, and 'c' is the hypotenuse.

Plug the numbers in and simplify.

Answer 3

@sbuck98 have you figured it out or are you stuck?

Answer 4

\[a^2+b^2 = c^2 \implies (5)^2 + (12)^2 = c^2 \] do you know how to solve for c?

Answer 5

I'm still stuck:(

Answer 6

5^2=5*5 = ?

Answer 7

25

Answer 8

Hint: \[x^2 = stuff \implies \sqrt{(x)^2} = \sqrt{stuff} \implies x = \sqrt{stuff}\] we'll stay away from plus/ minus for now :P

Answer 9

12^2=12*12=?

Answer 10

\[a^2+b^2=c^2
5^2+12^2==c^2
25+144=c^2\]
then subtract 144 from 25 and you get ur answer

Answer 11

@sbuck98 ?

Answer 12

so it's 119?

Answer 13

Nope
12 x 12=?

Answer 14

144

Answer 15

Good
25+144= ?

Answer 16

169

Answer 17

Perf now to isolate the c
\[\huge~\rm~\bf~\sqrt{c^2}=\sqrt{169}\]

Answer 18

25

Answer 19

oops sorry i meant add lol

Answer 20

not quite what's the square root of 169?

Answer 21

If you can't figure it out break it into factors
what numbers multiply to make 169?

Answer 22

84

Answer 23

nope...
12 x 12=144 right?
169 is a perfect square