Question

fan and medal pls help!!
simplify
sqrt9x^3 * sqrt18x

and

(27)^-2/3

i have multiple problems like this on the worksheet, so pls explain your steps if you can! i missed a week of alg2 and im lost

Answer 1

\[\sqrt{9x}.\sqrt{18x} = \sqrt{9.18.x.x} = \sqrt{3.3.3.3.2.x.x} = ???\]

Answer 2

\[26^{\frac{-2}{3}} = \frac{1}{27^{\frac{2}{3}}} = \frac{1}{\sqrt[3]{27*27}} = \frac{1}{\sqrt[3]{3.3.3.3.3.3}} = ??\]

Answer 3

i don't understand what the answer is??

Answer 4

\[\sqrt[3]{a.a.a} = a\]

Answer 5

and didn't you forget the ^3 in the first problem?

Answer 6

Yep yes I forgot.

Answer 7

and why is it 26, not 27 in the second problem?

Answer 8

insted of x.x it will become x.x.x.x

Answer 9

so is this answer to the second one 3?

Answer 10

first 26 is typo it should be 27

Answer 11

ohhh okay so the answer is 3?

Answer 12

There are total of 6's 3 so it should be 3.3 = 9 so 1 / 9.

Answer 13

okay thank you! could you possibly redo the first problem with the ^3?

Answer 14

\[\sqrt{9.9.x.x.x.x} = ??\]

Answer 15

i don't understand at all can you start from the beginning? @baljeet16

Answer 16

@AravindG ??

Answer 17

Yes sure

Answer 18

\[\sqrt{9x^{3}}\sqrt{18x} = \sqrt{9.x^3.18.x} = \sqrt{9.9.2.x^2.x^2} = ??\]

Answer 19

so is the answer 4x/18 ?? @baljeet16

Answer 20

where did you got 4 ??

Answer 21

the 4 x's

Answer 22

\[\sqrt{a.a} = a \\ \sqrt{a^2.a^2} = a^2\]

Answer 23

x/9 ??

Answer 24

\[9x.\sqrt{2}\]

Answer 25

OH okay

Answer 26

could you help me w two more problems??

Answer 27

yes sure.

Answer 28

simplify and rationalize denominators:
1. 6/8-sqrt3
2. sqrtw^4/a^3

Answer 29

@baljeet16

Answer 30

yes.

Answer 31

what? the questions are above @baljeet16

Answer 32

question 1 is not clear.

Answer 33

okay, i need to simplify the fraction 6/8 - sqrt 3

Answer 34

and rationalize the denominator

Answer 35

6/(8- sqrt3) is that better?

Answer 36

yes

Answer 37

okay, so what do i do?

Answer 38

\[\frac{6}{8 - \sqrt{3}} = \frac{6}{8 - 1.732} = ????\]

Can you use calculator.

Answer 39

no, no calculators :/

Answer 40

8-1.732 is 6.268 @baljeet16

Answer 41

so 6/6.268?

Answer 42

\[\sqrt{\frac{a^4}{x^3}} = \sqrt{\frac{a^2.a^2}{x^2.x}} = \frac{a}{x}.x^{\frac{-1}{2}}\]

Answer 43

yes

Answer 44

is that the final answer? (for the second one)

Answer 45

Can you understand the second explaination.

Answer 46

yes i understand what you did, but is that the final answer? @baljeet16

Answer 47

yes it is.

Answer 48

No its little wrong.

Answer 49

can you find whats wrong?

Answer 50

in second question?

Answer 51

should the answe be a/x^2 instead of a/x ? @baljeet16

Answer 52

or should the 1/2 be positive? @baljeet16

Answer 53

it should be\[\frac{a^2}{x}.x^{\frac{-1}{2}}\]

Answer 54

ohhh i see what you did @baljeet16

Answer 55

could you possibly help me with one last problem @baljeet16 ?? if not its okay uve helped me a ton

Answer 56

Okay ask.

Answer 57

simplify 6sqrt40 - 2sqrt90 - 3sqrt160

Answer 58

@baljeet16

Answer 59

\[6.\sqrt{2.2.10} - 2.\sqrt{3.3.10} - 3.\sqrt{4.4.10} = 6.2.\sqrt{10} - 2.3.\sqrt{10} - 3.4.\sqrt{10} = ???\]

Answer 60

5sqrt-10 ?

Answer 61

@baljeet16

Answer 62

-5 sqrt(10) yes

Answer 63

thank you!

Answer 64

sorry its \[-6.\sqrt{10}\]

Answer 65

okay, thanks!