Question

please help!

Answer 1

When your dividing, how do you find the \[2x^2\] term?

Answer 2

Does \[(x+3)(A) = (2x^x+C)\]
make sense?

Answer 3

So then \[Ax=2x^2,\text{ and } 3A=C\]

Answer 4

okay

Answer 5

wait are you saying the box A and C are 3?

Answer 6

nope, \[A*x = 2x^2\] and \[3x \ne 2x^2\]

Answer 7

oh okay

Answer 8

So A is?

Answer 9

2x

Answer 10

yep! and that means C is?

Answer 11

1?

Answer 12

\[C = (2x)*3\], since \[(x+3)A=2x^2+C\]

Answer 13

okay so c is 6x?

Answer 14

is it -12x^2?

Answer 15

so \[x*B=3x\] Which means B=3. So E = 6. not D. Earlier is wrong, it should read E.

Answer 16

okay so
a=2x
b=3
c=6x
e=6
are theses ones right?

Answer 17

Yep. so now what is the relationship between D,E, and -23?

Answer 18

-29?

Answer 19

cuz -29+6=-23

Answer 20

wait! 3*3 = 9 not 6.

Answer 21

ohh my bad

Answer 22

but yes, -?+9=-23

Answer 23

-32

Answer 24

-(32)+9=-23... so D = 32