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Mathematics 21 Online
OpenStudy (mtalhahassan2):

Need help!!

OpenStudy (shamim):

Question?????!!!!!

OpenStudy (mtalhahassan2):

OpenStudy (mtalhahassan2):

OpenStudy (mtalhahassan2):

what can I do after that part?

OpenStudy (mtalhahassan2):

@dayakar

OpenStudy (dayakar):

b) last step remove lim symbol just write answer 1/2

OpenStudy (dayakar):

what is ur question

OpenStudy (mtalhahassan2):

number c

OpenStudy (dayakar):

how do u get the second line

OpenStudy (mtalhahassan2):

i am using my slope of tangent formula

OpenStudy (mtalhahassan2):

@dayakar

OpenStudy (phi):

factoring out the 2, write your last expression as \[ \lim_{h\rightarrow 0 }\frac{2}{h}\left( \frac{1}{\sqrt{9+h}} - \frac{1}{3}\right) \] I would use a common denominator 3 sqr(9+h) and get the expression \[ \lim_{h\rightarrow 0 }\frac{2}{h}\left( \frac{3-\sqrt{9+h}}{3\sqrt{9+h}} \right) \] now multiply top and bottom by \( (3+\sqrt{9+h})\) the idea is up top we have (a-b)(a-b) = a^2 - b^2 and that gets rid of the square roots

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