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Mathematics 6 Online
OpenStudy (anonymous):

Man if you could help me out i'll plant a tree in your name. what is the graph of the rational function (x+2)(x+4)/(x+4)(x+1) looking for asymptotes and holes

OpenStudy (briannabug):

What do you think?

OpenStudy (anonymous):

Well if i knew what a hole was that would help haha

OpenStudy (anonymous):

yeah would help

OpenStudy (isaidavila):

Symplifing se got (x+2)/(x+1) Obviusly x could not be -1 so here is a hole

OpenStudy (mathmale):

Just to be clear: please type out the numerator of your rational fraction here. Next, type out the denominator here. Can this rational function be simplified by cancelling or reduction? Explain.

OpenStudy (anonymous):

So you could cancel out the x+4's leaving x+2/x+1 correct?

OpenStudy (isaidavila):

Yes

OpenStudy (anonymous):

So my confusion lies in why -1 would be a hole, but not -2. What is it i'm misunderstanding?

OpenStudy (isaidavila):

To find asymptotes just make a limit Lim x-->0 (x+2)/(x+1) that give us 2

OpenStudy (isaidavila):

Because when you replace -1 in the function it give us 1/0 and this is imposible so the function is not continous in this point

OpenStudy (anonymous):

ohh alright, thank you all for actually leading me to the answer instead of just giving it to me!

OpenStudy (isaidavila):

Ok No problem

OpenStudy (jdoe0001):

the numerator's equation has a degree of 1 the denominator's equation has a degree of 1 the leading term coefficient for each is 1 \(\bf \cfrac{{\color{brown}{ 1}} x^{\color{blue}{ 1}}+2}{{\color{brown}{ 1}} x^{\color{blue}{ 1}}+1}\quad thus\implies \cfrac{{\color{brown}{ 1}}}{{\color{brown}{ 1}}}\iff 1\implies y=1\impliedby \textit{horizontal asymptote}\)

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