Question

Help please

Answer 1

ok

Answer 2

What is your question?

Answer 3

Solve the equation.
x^2=160

Answer 4

do you want a direct answer or explaintion

Answer 5

Explanation please.

Answer 6

^2 means an exponet, which you have multiply the number by the number it says for example:
3 3 3 3
3^4 = _____ x _____ x _____x _______
there are four places for the number three

Answer 7

in this case, _____ x ____ = 160

Answer 8

Solve x^2=160. One way would be to take the square root of both sides.

Can y ou do that?

Answer 9

TheCleaverOne i ment square root

Answer 10

then just find the sme number that muliply together that equal that number

Answer 11

Mathmale it does not come out as a perfect square though.

Answer 12

you can round

Answer 13

12.64 is your answer

Answer 14

oh ok

Answer 15

Thank you!!! :D

Answer 16

care to fan and medal

Answer 17

True, 160 is not a perfect square. However, you can write Sqrt(160) as\[\sqrt{160}=\sqrt{10}\sqrt{16}\]

Answer 18

Note that 16 is a perfect square, so that the square root of 16 is easily found.

What is your final result? Remember, this is a quadratic equation, so you MUST write out 2 roots.

The roots of x^2-160=0 are: What?

Answer 19

4 and 10?

Answer 20

"care to fan and medal?" is not an appropriate request. See the Code of Conduct, please.

Answer 21

If x^2-160=0,
then x^2=160
Taking the sqrt of both sides results in x = plus or minus Sqrt(10)*Sqrt(16).

Yes, 4 is the sqrt of 16. Must leave sqrt(10) as is, since 10 is not a perfect square.

Answer 22

Can you help me with some more?

Answer 23

If you'll post them one by one, yes.

Answer 24

In general, the solution to

\(x^2 = k\)

where k is a number is

\(x = \pm \sqrt k\)

In your case, k = 160.
Find the square root as you did above, but don't forget the negative solution also.