Will medal.
If a sample is taken from a material is initially at 25degrees c, what is its final temperature if 150g of the material absorbs 1000j of heat, and the specific heat of the material is .96 j/g degrees c?

Question

Will medal. 
If a sample is taken from a material is initially at 25degrees c, what is its final temperature if 150g of the material absorbs 1000j of heat, and the specific heat of the material is .96 j/g degrees c?

anonymous · Answer

Don't mind the top part. See that's how I did it but I'm got an answer that doesn't match it.....

anonymous · Answer

oh the picture only shows up on the app?

anonymous · Answer

@tom982 @mathmale @pooja195 @zelda101

anonymous · Answer

Do you know what formula we can use here? Read up on heat capacity equations. You've been given heat, mass, heat capacity and starting temperature.

anonymous · Answer

ik what the formula is, and i worked it out, but when i got the initial time it was -18, and thats not correct

anonymous · Answer

1000j= 150g x .96 j/g degrees c x (  )

anonymous · Answer

i multiplied 150 x .96 and got 144 and divided 1000 by 144 and got -18

anonymous · Answer

so idk where i messed up

anonymous · Answer

Our equation is $Q=cm (T_{final}-T_{initial})$
So we have $1000=0.96*150(x-25)$
Solving for $x$ gives $31.9444444444$

anonymous · Answer

how tho

anonymous · Answer

sorry i have to explain my work

anonymous · Answer

Just a bit of rearranging.
$$1000=0.96*150(x-25)$$$$\frac{1000}{0.96*150}=x-25$$$$6.94444444444=x-25$$$$x=31.94444444444$$

anonymous · Answer

ok thanks, that makes a lot more sense

anonymous · Answer

No problem, happy to help.