Statement 1 :Two longitudinal waves givrn by equation : y1(x,t)=2asin(wt-kx) and y2(x,t)=asin(2wt-2kx) will have equal intensity Statement 2: Intensity of waves of given frequency in same medium is proportional to square of amplitude only... 1) Statement 1 is false,statement 2 is true 2) statement 2 is false ,statement 1 is true....
Intensity \(\alpha \) (amplitude)^2
So u mean ans is 2. ..
Sorry 1
yup
Bt the ans is 2
I were also getting same ans as urs...
O.o
\(\rm y2(x,t)=asin(2wt-2kx)\) \(\rm y1(x,t)=asin(\color{red}{2}wt-\color{red}{2}kx)\)
What u did in the equation of y1?
m joking LOL
Wow..it killed me ....
@Astrophysics =^-^=
@Directrix
@parthkohli pls..help
@mayankdevnani
As long as we are not told what type of wave it is and what y represents, we cannot decide if statement 1 is right or wrong.
Y is the displacement of wave particle in y direction ... N the y(x,t) represents that displacement of a particle of wave progressing towards x direction at a particular time t...
sound wave produced when any object get some disturbance , sound wave with same amplitude must have same a to have same intensity since these two equation dont have it , so we may conclude this two wave dont have same intensity. For the next question we can say that the intensity is actually the square of amplitude.
That's the way things seem to be taught in India : intensity of a mechanical wave depends on amplitude squared AND frequency squared. So, statement 1 is true since both intensities will be given by 4a²w² The real reason is different, namely because y does not lead to any meaningful energetical quantity (velocity does).
Have a look at my answer at the bottom of : http://openstudy.com/study#/updates/56b5ccafe4b067e118210e94
option 2 is correct answer !
@samigupta8
Yep it is....
@mayankdevnani wud u explain??
another tukka !
aur voh bhi sahi
Yrr pls tukka mat lagao...
lol..kya karu iske illava mujhe aati hi kya h
Bhut kuch...
Tarika btao plss
now be serious move onto your question
do you know the formula AVERAGE INTENSITY ?
Okk...i know it bt derivation is vague
derivation is too easy
Well , I will get the ans of this question if i know the derivation of it....
Tell ...then?
Now plss...don't say that power/area = intensity...
Okk...i should clearly say that i don't know the derivation of average power transmitted in a wave
god! power derivation is too long and too lenghty
*lengthy
Pls...do tell me
Okk, i will show u the derivation proposed by my sir...n in that i m confused over a particular part...u have to solve that ...will u ?
yep
So i will send to ur hangouts
i will suggest you that there is no time to study derivation.
go to formula and crack questions easily !
Arey pichle saal ka doubt h abhi tk chl ra h
and btw there is nothing need of derivation in this particular section.
Pls...open it. ..
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