Question

What are the solutions?

Answer 1

http://www.geteasysolution.com/x%5E2-5x-36=0

Answer 2

Hopefully that helps

Answer 3

what are the factors of 36?

Answer 4

9 and 4

Answer 5

hint: \(\begin{array}{cccllll}
x^2&-5x&-36&=0\\
&-9+4&-9\cdot 4
\end{array}\)

Answer 6

how can we add/subtract 9 and 4 to get -5

Answer 7

-3+-2=-5

Answer 8

4-9 = -5

Answer 9

so you have
\[x^2-5x-36\\
= x^2+(4-9)x+(4\times-9)\\
%= x\times x+(4x-9x)+(4\times-9)\\
= (x+...)(x+...)\]

Answer 10

(x+a)(x+b) = x(x+b)+a(x+b)
= x^2+bx+ax+ab
= x^2+(a+b)x+ab

Answer 11

the solutions will be -a and -b

Answer 12

Alright.

Answer 13

what do you get for the factored form of the equation?

Answer 14

I'm doing something wrong

Answer 15

yep, try again.

Answer 16

\[(x-9)(x+4)\]

Answer 17

@UnkleRhaukus

Answer 18

@surjithayer

Answer 19

so you have (x-9)(x+4) = 0

the solutions are when either (x-9) = 0, or (x+4) =0.

what solutions do you get?

Answer 20

Would I take the square root of the of 9 and 4?

Answer 21

no

Answer 22

solve x-9 = 0 for x

and solve x+4 = 0 for x

Answer 23

. . .

Answer 24

NO. i give up.