Question

Perimeter help?

A training field is designed by joining a rectangle and two semicircles. The rectangle is
98m long and 70m wide. What is the length of a training track running around the field? (Use the value 3.14 for π, and do not round your answer. Be sure to include the correct unit in your answer.)

Answer 1

First you would find the perimeter of the two semi circles....since there are two semi circles then they would make one whole circle so we can find the circumference of a whole circle so....

\(\Large\color{green}{C=\pi \times d}\) We know that we would substitute \(\large{3.14}\) for \(\large{\pi}\)....and \(\large{70}\) for \(\large{d}\)....So we substitute....

\(\Large\color{red}{C=3.14 \times 70}\) What would be the circumference?

Answer 2

C= 219.8m

Answer 3

p=336

Answer 4

hold on...

Answer 5

555.8m, or m^2, or m^3?

Answer 6

Sorry i messed up....the pereimeter of the rectangle would actually be 98+98 since 70 is part of the area of the track but we want to know the length so we would only do \(\Large{98+98}\)....

Answer 7

So once we get the perimeter of the rectangle we would add to find the length of the track....

\(\Large\color{red}{Length~of~Track=196+219.8}\)

Answer 8

im so sorry i messed up before....

Answer 9

415.8m or m^2

Answer 10

Since we found out the length it would only be \(\LARGE\color{red}{415.8m}\) becuase \(\Large{m^{2}}\)is for area....

Answer 11

Can you help me with another?

Answer 12

A semicircle is cut out of a rectangular paperboard 21in long and 17in wide. What is the perimeter of the paperboard that remains after the semicircle is removed?

Answer 13

try posting your question up in a new post to try and get more help...