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Mathematics 21 Online
OpenStudy (dontknowdontcare):

Need help with geometry, fan and medal!

OpenStudy (anonymous):

i got ya

OpenStudy (dontknowdontcare):

The figure below shows triangle NRM with r2 = m2 + n2:

OpenStudy (dontknowdontcare):

OpenStudy (dontknowdontcare):

Ben constructed a right triangle EFD with legs m and n, as shown below:

OpenStudy (anonymous):

I suppose you mean \[r^2=m^2+n^2\]

OpenStudy (dontknowdontcare):

OpenStudy (dontknowdontcare):

He made the following table to prove that triangle NRM is a right triangle:

OpenStudy (dontknowdontcare):

Statement Reason 1. r2 = m2 + n2 Given 2. f2 = m2 + n2 Pythagorean Theorem 3. f2 = r2 Substitution 4. f = r Square Root Property of Equality 5. Triangle NRM is congruent to triangle EFD SSS Postulate 6. Angle NRM is a right angle ? 7. Triangle NRM is a right triangle Angle NRM is a right angle Which reason best fits statement 6?

OpenStudy (anonymous):

okay

OpenStudy (dontknowdontcare):

Triangle Proportionality Theorem All sides of both the triangles are equal Corresponding parts of congruent triangles are congruent Triangle EFD has two angles which measure less than 90°

OpenStudy (dontknowdontcare):

any clue?

OpenStudy (anonymous):

it is SAS postulate not sss

OpenStudy (anonymous):

Not necessarily ^ you can use SSS, if you say that f and r are equal through CPCTC

OpenStudy (dontknowdontcare):

I didn't make this chart, there shouldn't be any mistakes, I just need to know which best goes for statement 6

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

Ummmm Not sure if any of these are the best answer possible It is obvious that it is a right angle through that you can only use pythagorean theorem on right angled triangles... So I'm not really sure

OpenStudy (anonymous):

since both triangle are congruent then NRM is SSS

OpenStudy (dontknowdontcare):

does that go into any of my answer choices? Im really lost

OpenStudy (anonymous):

I mean no .6

OpenStudy (dontknowdontcare):

Do you know what would justify that NRM is a right angle though?

OpenStudy (anonymous):

As far as I can tell it's none of those choices @dontknowdontcare none of them prove angular stuff The first one has to do with similarity The second is just SSS which doesn't get us anwhere CPCTC is useless because we haven't established that it is a right angle in any triangle The 4th could be applied to equilateral triangles as well

OpenStudy (anonymous):

So I honestly dont know

OpenStudy (dontknowdontcare):

Thanks for trying I'll just guess and if i figure out the answer ill post it :/

OpenStudy (anonymous):

Alright thanks^ because I'm curious too

Directrix (directrix):

Only the key steps are given in the proof which makes the logic difficult to follow in some steps. Of the options, I would go for: Corresponding parts of congruent triangles are congruent That comes right after proving the triangles congruent. Vertex R corresponds to vertex F which is the vertex of a right angle. That means that <R is congruent to <F which has measure 90. That gives <R a measure of 90 which makes it a right angle by definition of right angle. @dontknowdontcare

OpenStudy (dontknowdontcare):

@Directrix you were right it was C @Brill

OpenStudy (anonymous):

Alright thanks

Directrix (directrix):

Thanks for letting me know.

OpenStudy (dontknowdontcare):

can you help me with a few more? @Directrix

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