Question

Question below please help me work this out!!

Answer 1

\[\sqrt{2x+13}-5=x\]What is the solution of the equation?

Answer 2

@mathmale @newtonson

Answer 3

Have you worked with square roots before?

Answer 4

kinda my last problem delt with them but is was really hard for me to understand

Answer 5

I know how to do some of it so I will explain up until that point

Answer 6

okay thank you

Answer 7

When you have something in a square root you want to make groups of 2, in this case you have 2 "x" so you can bring that outside of the root

Answer 8

I'm not sure about the 13 because the square root of 13 is 3.605 etc.

Answer 9

i want to make the problem with the squrt on the other side with x but i cant remember how to

Answer 10

ooohh.....nvm..I did it wrong sorry about that

Answer 11

try making it so that the square root is by itself

Answer 12

Move 5 over so you have the square root on the left and (x+5) on the right

Answer 13

okay i have that

Answer 14

\[\sqrt{2x+13}=x+5\]

Answer 15

After that you want to square both sides, if you do that you get rid of the square root on the left and on the right you get (x+5)^2

Answer 16

okay i have that now

Answer 17

Have you done FOIL before?

Answer 18

\[2x+13=(x+5)^2\]

Answer 19

uhhh maybe i dont remember

Answer 20

FOIL stands for First Inner Outer Last. We have (x+5)^2 if you expand that you get
(x+5)(x+5) so you want to FOIL it, multiply the first, then multiply inner, then outer, then last

Answer 21

\[x \times x\]
\[x \times 5\]
\[x \times 5\]
\[5\times5\]

Answer 22

\[x^2\]
\[5x\]
\[5x\]
25

Answer 23

\[x ^{2}+10x+25=2x+13\]

Answer 24

\[13=x^2+8x+25\]

Answer 25

Take the 13 over to the right side

Answer 26

\[-12=x^2+8x\] is wat i got are you sure cuz it would make a 0 where the 13 was

Answer 27

x^2+8x+12

Answer 28

Have you done factoring before? Its basically reverse FOIL

Answer 29

\[x ^{2}+8x+12\]

Answer 30

ohhhhhh wait nvm i did it wrong

Answer 31

xD

Answer 32

So what you want to do is factor it

Answer 33

\[-12=x^2+8x\]

\[-20=x^2*x\]
\[-20=x^3\]
\[x=\sqrt[3]{20}\]

Answer 34

\[x ^{2}+8x+12\]

Its kind of hard to explain factoring online :C but its basically reverse FOIL, You want to see what numbers can add to get 8x and what numbers you can multiply to get 12
(x+2)(x+6)

Answer 35

that is what i got

Answer 36

Leave it so that \[x ^{2}+8x+12=0\]

Answer 37

well then you still have to subtract the 12 for the other side making it \[-12=x^2+8x\]

Answer 38

Do you remember how we had
\[13=x ^{2}+8x+25\]

You want to take away 13 from both sides. \[13-13=x ^{2}+8x+25-13\]

Answer 39

ya

Answer 40

0=\[0= x ^{2}+8x+12\]

Answer 41

Then you want to factor it.

Answer 42

how??

Answer 43

It's kind of hard to explain :C but if you do those steps you should be able to get (x+2)(x+6)

Answer 44

after that you have x+2=0 and x+6=0 solve for x on both of them to get
x=-2
x=-6

Answer 45

okay thanks ive really been struggling

Answer 46

wait xD you have to plug it in to see if they are right

Answer 47

i did

Answer 48

okie :D

Answer 49

:D thanks for the help

Answer 50

sorry about the factoring stuff, I'm not the best at explaining that

Answer 51

Np :D