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Mathematics 30 Online
OpenStudy (pulsified333):

Let f(x) be the function whose graph is shown below. Determine f′(a) for a=1,2,4,7. f′(1)= f′(2)= f′(4)= f′(7)=

OpenStudy (pulsified333):

OpenStudy (pulsified333):

@dan815

OpenStudy (pulsified333):

im still here if anyone wants to answer

OpenStudy (unklerhaukus):

f'(a) is the slope of f(x) at the point x=a

OpenStudy (pulsified333):

okay

OpenStudy (unklerhaukus):

what is the slope of the function at x=a=1?

OpenStudy (pulsified333):

0

OpenStudy (unklerhaukus):

good!,

OpenStudy (pulsified333):

same for 2

OpenStudy (unklerhaukus):

yes!

OpenStudy (unklerhaukus):

what about at the point x=a=4?

OpenStudy (pulsified333):

-4.666667

OpenStudy (pulsified333):

ish

OpenStudy (pulsified333):

wait

OpenStudy (unklerhaukus):

hmm, no, the slope is positive here

OpenStudy (pulsified333):

1/2

OpenStudy (unklerhaukus):

good!

OpenStudy (unklerhaukus):

and the last one f'(7) = ?

OpenStudy (pulsified333):

is it 0?

OpenStudy (unklerhaukus):

yes, x=7 is the point at the bottom of the curvy bit

OpenStudy (unklerhaukus):

it is zero.

OpenStudy (pulsified333):

Thanks man :D

OpenStudy (unklerhaukus):

Good work. Note that at the points x=a = 3 or = 5 (the corner points) the slope/derivative are not defined.

OpenStudy (pulsified333):

ah okay

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