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Let f(x) be the function whose graph is shown below. Determine f′(a) for a=1,2,4,7. f′(1)= f′(2)= f′(4)= f′(7)=
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@dan815
im still here if anyone wants to answer
f'(a) is the slope of f(x) at the point x=a
okay
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what is the slope of the function at x=a=1?
0
good!,
same for 2
yes!
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what about at the point x=a=4?
-4.666667
ish
wait
hmm, no, the slope is positive here
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1/2
good!
and the last one f'(7) = ?
is it 0?
yes, x=7 is the point at the bottom of the curvy bit
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it is zero.
Thanks man :D
Good work. Note that at the points x=a = 3 or = 5 (the corner points) the slope/derivative are not defined.
ah okay
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