Question

NEED HELP

Answer 1

on what

Answer 2

Here to help !

Answer 3

Using Identities you get\[\log_{2} \frac{ k^5 }{ m^8 }+\log_{2} n^{10}\]

Answer 4

Then using the addition identity you can get
\[\log_{2} \frac{ k^5n^{10} }{ m^8 }\]

Answer 5

And I'm pretty sure that's as simplified as you can make it

Answer 6

damn brill you got some brains you'll make it to 99 ss in no time

thanks though do you think you can help me another one ?

Answer 7

Sure go ahead

Answer 8

@Brill wait can i review this one with you again

Answer 9

Sure go ahead where do you need clarification?

Answer 10

so i get the 5 and 10 go in the corners but why does m^8 go below

Answer 11

Because of this identity log(a/b) = log(a) - log(b)

Answer 12

It doesn't matter what base the log is, this always applies

So in this case n^5 is a and m^8 is b

Answer 13

you mean
n^10 right ?

Answer 14

Wait no sorry

You HAVE to do the FIRST two terms FIRST because that is order of operation

So that makes it k^5/m^8

Answer 15

The n^10 later gets added on due to this property log(ab) = log(a) + log(b)

Answer 16

Where a is k^5/m^8 and b is n^10

Answer 17

And this gets you log2(k^5n^10/m^8

Answer 18

Sorry my bad if I confused you

Answer 19

lol no.. thank you this log stuff confuses me in general

Answer 20

So think you can do the other one now?
Or do you need me to give you a jump start to simplify that one?

Answer 21

a jump start would be great

Answer 22

wait nvm i got it thank you