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Mathematics 18 Online
OpenStudy (anonymous):

Which interval for the graphed function has a local minimum of 0? Plz help https://media.education2020.com/evresources/3109/3109-02/3109-02-04/3109-02-04-assessment/3109-02-04-assessments-11.png [–3, –2] [–2, 0] [1, 2] [2, 4]

OpenStudy (fortytherapper):

A local minimum, in human terms, is when the graph switches direction from downward to upward. Do you see any points where that switch happens? (There are two X values)

OpenStudy (anonymous):

I dont see where they switch

OpenStudy (fortytherapper):

Ill show you one. Look at the point (-1.56, -6). The x being -1.56 because (x,y) See how the graph is going downward before that point and then upwards after that point? Is there another place on the graph where it goes downward before the point, and then upwards after?

OpenStudy (anonymous):

im thinking its going up to (0,0)

OpenStudy (anonymous):

maybe not

OpenStudy (fortytherapper):

(0,0) wouldn't be a local minimum because if you look at how the line is to the left of the point, it's not going downward, right?

OpenStudy (anonymous):

yeah

OpenStudy (fortytherapper):

So which point on the graph, if you look to the left of that point, is the line going down on the left side, but also going up on the right side of the point?

OpenStudy (anonymous):

its going up its going to be (-2, 0)

OpenStudy (fortytherapper):

(-2,0) is an interval [Answer choice], which are different from points. You can only find the point on the actual graph But the point is (3,0). If you look at (3,0). Look to the left, the line is going down, right? and to the right, it goes up

OpenStudy (anonymous):

(1,2) Am I correct now?

OpenStudy (fortytherapper):

Howd you get that?

OpenStudy (anonymous):

counted up to the right

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