ab is a two digit number. When ab is divided by 7 the remainder is 3. Find the sum of all positive values of ab.
Merhaba bir dakika yardım edeceğim
ingilizce mi soyleyim türkçe mi
Doesnt matter, so to start with find all the numbers that are multiples of 7 and two digits: (14,21,28,35,42,49,56,63,70,77,84,91,98)
Now you have to find a pattern which you can use: So start with 14, when you divide it by 7 you get no remainder when you divide 13 by 7 you get 6 remainder when you divide 12 by 7 you get 5 remainder when you divide 11 by 7 you get 4 remainder And finally when you divide 10 by 7 you get 3 as remainder This means that the values you are looking for are x-4 ( where x are two digit multiples of 7)
So your new list of two digits with 3 remainder when divided by 7 will be in a manner such as 14-4 , 21-4, 28-4 and so on till you get to 98-4 Tell me if you understand
I understand till now @denonakavro
Ok, so lets continue The value we are looking for is the sum of our new list So let me do the list for you (10,17,24,31,38,45,52,59,66,73,80,87,94) Now just add all these up and tell me what you get ?
I get 676 in total
Yes thats what I got too :) and should be the answer Btw, are you from Turkey ?
Thank you for your really clear answer that was very helpful. Yes, I am from Turkey. How about you?
Ilk başta yazdım ama görmemişsin ben de türküm
Türk olduğunu elbette anladım ama Türkiye'de mi yaşıyorsun demek istedim.
Yaşıyordum diyelim, bir süredir yurt dışında yaşıyorum ve eğitim görüyorum. Herhangi bir matematik konusunda veya başka konularda yardım gerekirse soyleyebilirsin
Eğer olursa söylerim, tekrardan çok teşekkürler.
Rather than totalling them all using a calculator you should treat it as an arithmetic series with common difference = 7
I found the general term as Un=7n+3 and did the equations by that @MrNood
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