Can you help me
whats the question :)
From the table above: If the researcher was to choose 2 people at random (assume when a person is chosen, they are not eligible to be chosen again), what is the probability that the 1st person she chooses lives in Los Angeles and the 2nd person she chooses lives in Los Angeles? A. 6/20 or 30% B. 5/19 or 26.3% C. 30/380 or 7.9% D. 36/400 or 9% E. 30/400 or 7.5%
I'm sorry but This Question I dont get
But I might have someone who can help you with this question
@hartnn
so both the person she chooses need to live in Los Angeles?
Out of 20 total people, how many of them live in Los Angeles??
1st 6 , right? so probability of choosing 1 person out of 20 who lives in Los Angeles is just 6/20.
now we have 19 others left, and 5 people living in Los Angeles left.
so probability of again choosing a person living in Los Angeles = 5/19
multiply these 2 answers to get your final answer :)
sorry, i thought you left, otherwise i would have waited for your responses...
30/380
\(\huge \checkmark \)
Yes it looks what way
But can it be reduced or no
No it cannot that I see
Yes but look at your options, there is no need to reduce it.
my bad I was mistaken
From the same table: If the researcher was to choose 3 people at random (assume when a person is chosen, they are not eligible to be chosen again), what is the probability that all 3 people she chooses will be over 50 years old?
total how many people are there with age more than 50 ?
6
is it 6/20*5/19*4/18
correct!
so 120/6840
the choices are these BTW. A. 120/6840 or 1.8% B. 120/8000 or 1.5% C. 216/8000 or 2.7% D. 216/6840 or 3.2% E. 150/7200 or 2.1%
yeah, 1st one
I have one more, From the table above If the researcher was to choose one person at random, what is the probability she would choose a person who lives in San Francisco or has experienced a major earthquake?
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