Question

Consider 4.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.00 L and the temperature is increased to 36 ∘C , what is the new pressure, P2, inside the container? Assume no change in the amount of gas inside the cylinder. So, P2=_____mmHg.

Answer 1

we know the amount of moles is the same

Answer 2

please help i think i am way off when i tried to work the problem

Answer 3

We know that pressure, volume and temperature are changing right?

\[pV = nRT \]

Essentially the changes in pressure temperature and volume are all happening where the number of moles is a constant.

\[\frac{ pV }{ T } = nR \]

now, we go like this, we're asked to find the new pressure, so this is the formula we get and must use for our problem.

\[\frac{ p_{1}v_{1} }{ T_{1} } = \frac{ p_{2}v_{2} }{ T_{2} }\]

now we're asked to solve for pressure 2.

we can re-write our formula to solve for the second pressure. so this is what we get.

\[\frac{ P_{1}V_{1}*T_{2} }{ T_{1}V_{2} } = P_{2}\]

all we do is plug in what we're given.

Answer 4

@sistergrl4 don't worry i'll help you

Answer 5

take a look at what I wrote above

Answer 6

ok so p1 is 4.00L and P2 is 2.00L

Answer 7

and the V1 and V2 are the temperatures?

Answer 8

V = VOLUME
P = pressure
T = temperature

Answer 9

ok so V1-4.00L, V2-2.00L and T1-20'C and T2-36'C

Answer 10

yes

Answer 11

what about the gas

Answer 12

but remember @sistergrl4 we need to convert the temperature to Kelvins. to do that

you need to add the temperature in C+273 = K

Answer 13

our temperatures are in celcius and it wont work out for this problem.

Answer 14

oh ok

Answer 15

do i add 20 and 36 to 273=K

Answer 16

please work with me i feel kinda dumb because i havent done chemistry in a while

Answer 17

20+273 = Kelvins for temperature 1

36 + 273 = Kelvins for temperature 2

Answer 18

1-293 K
2-309K

Answer 19

great

Answer 20

now

we have

T1 = 293K
P1 = 0.48 atm
V1 = 4.0 L

T2 = 309k
V2 = 2L
P2 = ?

So all you have to do now is enter all your information into this formula

\[\frac{ P_{1}V_{1}T_{2} }{ T_{1}*V_{2} }\]

Answer 21

OK FOR P1 V1 T2 DO I ADD OR MULTIPLY THE TOP NUMBERS

Answer 22

multiply :)

Answer 23

OK I AM MULTIPLYING

Answer 24

\[\frac{ 0.48atm*4.0L*309k }{ 293K*2L } = P_{2}\]

Answer 25

562.56/ 293*2L= 562.56/586=0.96p2

Answer 26

Almost :) I got something like 1.01 atm

Answer 27

oh man

Answer 28

what did i do wrong

Answer 29

remember we can convert this easily to mmHG by multiplying 1.01*760

so we'd get 767.6 mmHG

Answer 30

thanks

Answer 31

anytime :)