Mathematics
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OpenStudy (i_need_help_please):
Will Fan and Medal
AC=BC, AB=6
How long are each of the Legs?
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OpenStudy (i_need_help_please):
|dw:1456154701749:dw|
hartnn (hartnn):
is C a right angle?
if yes, you can use pythagoras theorem :)
OpenStudy (i_need_help_please):
yes it is.
OpenStudy (i_need_help_please):
i was trying to use the Pythagorean theorem but it wasn't working out for me. I couldn't figure out how to do it correctly with this problem.
hartnn (hartnn):
did you get something like
\(x^2 +x^2 = 6^2\) ?
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OpenStudy (i_need_help_please):
yes
hartnn (hartnn):
\(2x^2 = 36 \\x^2 = 18\)
just take square root on both sides
OpenStudy (i_need_help_please):
sqrt18= 3sqrt 2
sqrt 36=6
hartnn (hartnn):
\(x^2 = 18 \\ x = \pm 3 \sqrt 2\)
thats it!
OpenStudy (i_need_help_please):
thats what i was doing but then is 3 sqrt. 2 the lengths of the two sides because if so they dont add up to 6.
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hartnn (hartnn):
why would the lengths of 2 sides add up to 6 ???
OpenStudy (i_need_help_please):
the length squared* dont add up to 6^2
OpenStudy (i_need_help_please):
to do the Pythagorean theorym
hartnn (hartnn):
is it?
\((3\sqrt2)^2 + (3\sqrt 2 )^2 \\ = 18 +18 = 36 = 6^2\)
OpenStudy (i_need_help_please):
okay. so both of the lengths are definitely 3sqrt. 2?
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hartnn (hartnn):
yup :)
OpenStudy (i_need_help_please):
Okay, Thanks so much!
hartnn (hartnn):
welcome ^_^